b/a = ?
Since 9×16 = 12², (9ᵏ, 12ᵏ, 16ᵏ) = (a, b, a + b) forms a geometric triple whose common ratio λ = b/a = (a + b)/b clearly satisfies, for some k, the characteristic relation of the golden ratio. Thus, required b/a = φ
b/a = ?
Since 9×16 = 12², (9ᵏ, 12ᵏ, 16ᵏ) = (a, b, a + b) forms a geometric triple whose common ratio λ = b/a = (a + b)/b clearly satisfies, for some k, the characteristic relation of the golden ratio. Thus, required b/a = φ
