se a + b + c = 1580. e inoltre a/b+c + b /c+a + c/a+b = 76, calcoliamo
a/(b+c)+b/(c+a)+c/(a+b)=76
c/(a+b)+1+a/(b+c)+1+b/(c+a)+1=76+3
(a+b+c)/(a+b)+(a+b+c)/(b+c)+(a+b+c)/(c+a)=79
(a+b+c)*[1/(a+b)+1/(b+c)+1/(c+a)]=79
1580*[1/(a+b)+1/(b+c)+1/(c+a)]=79
1/(a+b)+1/(b+c)+1/(c+a)=79/1580=1/20
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